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+ Given strings s1, s2, and s3, find whether s3 is formed by an interleaving of s1 and s2.
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+ An interleaving of two strings s and t is a configuration where s and t are divided into n and m substrings respectively, such that:
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+ s = s1 + s2 + ... + sn
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+ t = t1 + t2 + ... + tm
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+ |n - m| <= 1
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+ The interleaving is s1 + t1 + s2 + t2 + s3 + t3 + ... or t1 + s1 + t2 + s2 + t3 + s3 + ...
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+ Note: a + b is the concatenation of strings a and b.
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+ Example 1:
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+ Input: s1 = "aabcc", s2 = "dbbca", s3 = "aadbbcbcac"
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+ Output: true
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+ Explanation: One way to obtain s3 is:
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+ Split s1 into s1 = "aa" + "bc" + "c", and s2 into s2 = "dbbc" + "a".
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+ Interleaving the two splits, we get "aa" + "dbbc" + "bc" + "a" + "c" = "aadbbcbcac".
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+ Since s3 can be obtained by interleaving s1 and s2, we return true.
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+ Example 2:
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+ Input: s1 = "aabcc", s2 = "dbbca", s3 = "aadbbbaccc"
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+ Output: false
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+ Explanation: Notice how it is impossible to interleave s2 with any other string to obtain s3.
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+ Example 3:
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+ Input: s1 = "", s2 = "", s3 = ""
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+ Output: true
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+ Constraints:
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+ 0 <= s1.length, s2.length <= 100
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+ 0 <= s3.length <= 200
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+ s1, s2, and s3 consist of lowercase English letters.
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+ Follow up: Could you solve it using only O(s2.length) additional memory space?
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