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immutable-tuple Build Status

Immutable finite list objects with constant-time equality testing (===) and no memory leaks.

Installation

First install the package from npm:

npm install immutable-tuple

or clone it from GitHub and then run npm install to compile the source code:

git clone https://github.com/benjamn/immutable-tuple.git
cd immutable-tuple
npm install
npm test # if skeptical

Usage

The npm package exports a single function called tuple, both as a default export and as an equivalent named export, so all of the following import styles will work:

import tuple from "immutable-tuple";
import { tuple } from "immutable-tuple";
const { tuple } = require("immutable-tuple");
const tuple = require("immutable-tuple").tuple;

The tuple function takes any number of arguments and returns a unique, immutable object that inherits from tuple.prototype and is guaranteed to be === any other tuple object created from the same sequence of arguments:

import assert from "assert";

const obj = { asdf: 1234 };
const t1 = tuple(1, "asdf", obj);
const t2 = tuple(1, "asdf", obj);

assert.strictEqual(t1 === t2, true);
assert.strictEqual(t1, t2);

The tuple object has a fixed numeric .length property, and its elements may be accessed using array index notation:

assert.strictEqual(t1.length, 3);
t1.forEach((x, i) => {
  assert.strictEqual(x, t2[i]);
});

Since tuple objects are just another kind of JavaScript object, naturally tuples can contain other tuples:

assert.strictEqual(
  tuple(t1, t2),
  tuple(t2, t1)
);

assert.strictEqual(
  tuple(1, t2, 3)[1][2],
  obj
);

However, because tuples are immutable and always distinct from any of their arguments, it is not possible for a tuple to contain itself, nor to contain another tuple that contains the original tuple, and so forth.

Since tuple objects are identical when (and only when) their elements are identical, any two tuples can be compared for equality in constant time, regardless of how many elements they contain.

This behavior also makes tuple objects useful as keys in a Map, or elements in a Set, without any extra hashing or equality logic:

const map = new Map;

map.set(tuple(1, 12, 3), {
  author: tuple("Ben", "Newman"),
  releaseDate: Date.now()
});

const version = "1.12.3";
const info = map.get(tuple(...version.split(".").map(Number)));
if (info) {
  console.log(info.author[1]); // "Newman"
}

Every non-destructive method of Array.prototype is supported by tuple.prototype, including sort and reverse, which return a modified copy of the tuple without altering the original:

assert.strictEqual(
  tuple("a", "b", "c").slice(1, -1),
  tuple("b")
);

assert.strictEqual(
  tuple(6, 2, 8, 1, 3, 0).sort(),
  tuple(0, 1, 2, 3, 6, 8)
);

assert.strictEqual(
  tuple(1).concat(2, tuple(3, 4), 5),
  tuple(1, 2, 3, 4, 5)
);

While the identity, number, and order of elements in a tuple is fixed, please note that the contents of the individual elements are not frozen in any way:

const obj = { asdf: 1234 };
tuple(1, "asdf", obj)[2].asdf = "oyez";
assert.strictEqual(obj.asdf, "oyez");

Garbage collection

Any data structure that guarantees === equality based on structural equality must maintain some sort of internal pool of previously encountered instances.

Implementing such a pool for tuples is fairly straightforward (though feel free to give it some thought before reading this code, if you like figuring things out for yourself):

const pool = new Map;

function tuple(...items) {
  let node = pool; 

  items.forEach(item => {
    let child = node.get(item);
    if (!child) node.set(item, child = new Map);
    node = child;
  });

  // If we've created a tuple instance for this sequence of elements before,
  // return that instance again. Otherwise create a new immutable tuple instance
  // with the same (frozen) elements as the items array.
  return node.tuple || (node.tuple = Object.create(
    tuple.prototype,
    Object.getOwnPropertyDescriptors(Object.freeze(items))
  ));
}

This implementation is pretty good, because it requires only linear time (O(items.length)) to determine if a tuple has been created previously for the given items, and you can't do better than linear time (asymptotically speaking) because you have to look at all the items. This code is also useful as an illustration of exactly how the tuple constructor behaves, in case you weren't satisfied by my examples in the previous section.

However, this simple implementation has a serious problem: in a garbage-collected language like JavaScript, the pool itself will retain references to all tuple objects ever created, which prevents tuple objects and their elements (which may be very large objects) from ever being reclaimed by the garbage collector, even after they become unreachable by any other means. In other words, storing objects in this kind of tuple would inevitably cause memory leaks.

To solve this problem, it's tempting to try changing Map to WeakMap here:

const pool = new WeakMap;

and here:

if (!child) node.set(item, child = new WeakMap);

This approach is appealing because a WeakMap should allow its keys to be reclaimed by the garbage collector. That's the whole point of a WeakMap, after all. Once a tuple becomes unreachable because the program has stopped using it anywhere else, its elements are free to disappear from the pool of WeakMaps whenever they too become unreachable. In other words, something like a WeakMap is exactly what we need here.

Unfortunately, this strategy stumbles because a tuple can contain primitive values as well as object references, whereas a WeakMap only allows keys that are object references. In other words, node.set(item, ...) would fail whenever item is not an object, if node is a WeakMap. To see how the immutable-tuple library gets around this WeakMap limitation, have a look at this module.

Astute readers may object that some bookkeeping data remains in memory when you create tuple objects with prefixes of primitive values, but the important thing is that no user-defined objects are kept alive by the pool. That said, if you have any ideas for reclaiming chains of ._strongMap data, please open an issue or submit a pull request!