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majority-element/README.md

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<h2>169. Majority Element</h2><h3>Easy</h3><hr><div><p>Given an array <code>nums</code> of size <code>n</code>, return <em>the majority element</em>.</p>
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<p>The majority element is the element that appears more than <code>⌊n / 2⌋</code> times. You may assume that the majority element always exists in the array.</p>
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<p>&nbsp;</p>
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<p><strong>Example 1:</strong></p>
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<pre><strong>Input:</strong> nums = [3,2,3]
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<strong>Output:</strong> 3
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</pre><p><strong>Example 2:</strong></p>
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<pre><strong>Input:</strong> nums = [2,2,1,1,1,2,2]
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<strong>Output:</strong> 2
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</pre>
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<p>&nbsp;</p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>n == nums.length</code></li>
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<li><code>1 &lt;= n &lt;= 5 * 10<sup>4</sup></code></li>
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<li><code>-2<sup>31</sup> &lt;= nums[i] &lt;= 2<sup>31</sup> - 1</code></li>
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</ul>
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<p>&nbsp;</p>
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<strong>Follow-up:</strong> Could you solve the problem in linear time and in <code>O(1)</code> space?</div>

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