Add division by 0 rules in the expression simplification

[HaoYang670]

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❯ create table t as select 1 as a;

❯ explain select a / 0 from t;
+---------------+--------------------------------------------------+
| plan_type     | plan                                             |
+---------------+--------------------------------------------------+
| logical_plan  | Projection: #t.a / Int64(0)                      |
|               |   TableScan: t projection=[a]                    |
| physical_plan | ProjectionExec: expr=[a@0 / 0 as t.a / Int64(0)] |
|               |   MemoryExec: partitions=1, partition_sizes=[1]  |
|               |                                                  |
+---------------+--------------------------------------------------+

❯ select a / 0 from t;
ArrowError(DivideByZero)

❯ explain select 1 / 0 from t;
+---------------+----------------------------------------------------+
| plan_type     | plan                                               |
+---------------+----------------------------------------------------+
| logical_plan  | Projection: Int64(NULL) AS Int64(1) / Int64(0)     |
|               |   TableScan: t projection=[a]                      |
| physical_plan | ProjectionExec: expr=[NULL as Int64(1) / Int64(0)] |
|               |   MemoryExec: partitions=1, partition_sizes=[1]    |
|               |                                                    |
+---------------+----------------------------------------------------+
2 rows in set. Query took 0.004 seconds.

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When the divisor is the scalar zero, We could one of these:

1. Simplify the expression to null -> A / 0 -> NULL
2. Give the DivideByZero error: A / 0 -> Err(DivideByZero)

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[askoa]

Per the below comment, we should not simplify errors as it might be unreachable during execution.

#3669 (comment)

cc: @alamb

[alamb]

Update here is that postgres errors too so we will keep the erroring behavior. Thanks @askoa

[retikulum]

Didn't #3824 close this or am I missing something?

[alamb]

I agree that #3824 closed this -- thanks @retikulum