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BJ001-1904150 Week2 homework #305

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23 changes: 23 additions & 0 deletions Week_02/id_150/leetcode_609_BJ001-1904150.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,23 @@
class Solution(object):
def findDuplicate(self, paths):
"""
:type paths: List[str]
:rtype: List[List[str]]
"""
dd = {}
for path in paths:
plist = path.split(" ")
prefix = plist[0];
for i in range(1, len(plist)):
route = prefix + "/" + plist[i].split("(")[0]
content = plist[i].split("(")[1].split(")")[0]
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你这方案倒是不错,能加点注释说明思路吗?

if content not in dd:
dd[content] = []
dd[content].append(route)

res = []
for key in dd:
if len(dd[key]) > 1:
res.append(dd[key])

return res
31 changes: 31 additions & 0 deletions Week_02/id_150/leetcode_671_BJ001-1904150.cpp
Original file line number Diff line number Diff line change
@@ -0,0 +1,31 @@
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/

class Solution {
public:
int findSecondMinimumValue(TreeNode* root) {
if(root == NULL && root->left == NULL)
return -1;
long long ans = findmin(root, root->val);
return ans == 2147483648 ? -1 : ans;
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2147483648 是什么魔法数字?同学加点注释说说你的思路吧

}

long long findmin(TreeNode* root, int val) {
if(root) {
if(root->val > val) {
return root->val;
}
return min(findmin(root->left, val), findmin(root->right, val) );
}
return 2147483648;
}
};


43 changes: 43 additions & 0 deletions Week_02/id_150/leetcode_692_BJ001-1904150.cpp
Original file line number Diff line number Diff line change
@@ -0,0 +1,43 @@
typedef pair<string, int> P;
struct cmp
{
bool operator()(const P p1, const P p2)
{
if(p1.second != p2.second)
return p1.second < p2.second;
return p1.first > p2.first;
}

};

class Solution {
public:
vector<string> topKFrequent(vector<string>& words, int k) {
vector<string> ans;

map<string, int> mp;
map<string, int> :: iterator iter;
for(int i = 0; i < words.size(); i++) {
string tmp = words[i];
if(mp.find(tmp) != mp.end()) {
mp[tmp]++;
} else {
mp[tmp] = 1;
}
}

priority_queue<P, vector<P>, cmp> que;
for(iter = mp.begin(); iter != mp.end(); iter++) {
que.push(P(iter->first, iter->second));
}

while(ans.size() != k) {
P tmp = que.top();
ans.push_back(tmp.first);
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你这没法保证频次相同的按字母顺序排呀

que.pop();
}

return ans;
}
};