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12.IntegerToRoman.cpp
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12.IntegerToRoman.cpp
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/*
* @lc app=leetcode id=12 lang=cpp
*
* [12] Integer to Roman
*
* https://leetcode.com/problems/integer-to-roman/description/
*
* algorithms
* Medium (54.91%)
* Likes: 1218
* Dislikes: 2746
* Total Accepted: 384.6K
* Total Submissions: 694.3K
* Testcase Example: '3'
*
* Roman numerals are represented by seven different symbols: I, V, X, L, C, D
* and M.
*
*
* Symbol Value
* I 1
* V 5
* X 10
* L 50
* C 100
* D 500
* M 1000
*
* For example, two is written as II in Roman numeral, just two one's added
* together. Twelve is written as, XII, which is simply X + II. The number
* twenty seven is written as XXVII, which is XX + V + II.
*
* Roman numerals are usually written largest to smallest from left to right.
* However, the numeral for four is not IIII. Instead, the number four is
* written as IV. Because the one is before the five we subtract it making
* four. The same principle applies to the number nine, which is written as IX.
* There are six instances where subtraction is used:
*
*
* I can be placed before V (5) and X (10) to make 4 and 9.
* X can be placed before L (50) and C (100) to make 40 and 90.
* C can be placed before D (500) and M (1000) to make 400 and 900.
*
*
* Given an integer, convert it to a roman numeral. Input is guaranteed to be
* within the range from 1 to 3999.
*
* Example 1:
*
*
* Input: 3
* Output: "III"
*
* Example 2:
*
*
* Input: 4
* Output: "IV"
*
* Example 3:
*
*
* Input: 9
* Output: "IX"
*
* Example 4:
*
*
* Input: 58
* Output: "LVIII"
* Explanation: L = 50, V = 5, III = 3.
*
*
* Example 5:
*
*
* Input: 1994
* Output: "MCMXCIV"
* Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.
*
*/
// @lc code=start
#include <string>
#include <vector>
#include <algorithm>
class Solution {
public:
std::string intToRoman(int num) {
std::string result = "";
// 0 ~ 9
helper(num, 'I', 'V', 'X', result);
num /= 10;
// 10 ~ 90
helper(num, 'X', 'L', 'C', result);
num /= 10;
// 100 ~ 900
helper(num, 'C', 'D', 'M', result);
num /= 10;
// 1000 ~ 3000
if (num > 0) {
result += std::string(num, 'M');
}
std::reverse(result.begin(), result.end());
return result;
}
private:
void helper(int num, char small, char median, char large, std::string& result) {
if (num == 0) return;
int res = num % 10;
if (res <= 3) {
result += std::string(res, small);
} else if (res == 4) {
result += median;
result += small;
} else if (res <= 8) {
result += std::string(res - 5, small);
result += median;
} else {
result += large;
result += small;
}
}
};
// @lc code=end