Diagonal Difference.py

'''
Given a square matrix, calculate the absolute difference between the sums of its diagonals.

For example, the square matrix  is shown below:

1 2 3
4 5 6
9 8 9  
The left-to-right diagonal = . The right to left diagonal = . Their absolute difference is .

Function description

Complete the  function in the editor below. It must return an integer representing the absolute diagonal difference.

diagonalDifference takes the following parameter:

arr: an array of integers .
Input Format

The first line contains a single integer, , the number of rows and columns in the matrix . 
Each of the next  lines describes a row, , and consists of  space-separated integers .

Constraints

Output Format

Print the absolute difference between the sums of the matrix's two diagonals as a single integer.

Sample Input

3
11 2 4
4 5 6
10 8 -12
Sample Output

15
'''
#Solution

#!/bin/python3

import math
import os
import random
import re
import sys

# Complete the diagonalDifference function below.
def diagonalDifference(arr):
    ln = len(arr)
    rowlen = len(arr[0])
    
    sum1 =0
    count =0
    sum2=0
    for j in range (rowlen):
        sum1 = sum1 + arr[j][count]
        count = count + 1
    count =ln -1
    for j in range (rowlen):
        sum2 = sum2 + arr[count][j]
        count = count - 1
    
    return abs (sum1-sum2)

    


if __name__ == '__main__':
    fptr = open(os.environ['OUTPUT_PATH'], 'w')

    n = int(input())

    arr = []

    for _ in range(n):
        arr.append(list(map(int, input().rstrip().split())))

    result = diagonalDifference(arr)

    fptr.write(str(result) + '\n')

    fptr.close()