Merge pull request #13 from priyadarshan1995/master

Program to find second largest element in a list

Author: Tanmay-901

second-largest-num.py

@@ -0,0 +1,18 @@
+# Program to find second largest element in list
+# Time Complexity : O(N)
+# run cmd: python3 second-largest-num.py
+
+class Solution:
+    def secondLargest(self, l):
+        mx=max(l[0],l[1]) 
+        secondmx=min(l[0],l[1]) 
+        n =len(l)
+        for i in range(2,n): 
+            if l[i]>mx: 
+                secondmx=mx
+                mx=l[i] 
+            elif l[i]>secondmx and mx != l[i]: 
+                secondmx=l[i]
+        return secondmx
+ 
+print("Second Largest number is :", Solution().secondLargest([12,412,11,42,10,1]))