Add Refactor

Author: Superklok

JavaScriptFlippingAnImage.md

@@ -21,17 +21,21 @@ To invert an image means that each `0` is replaced by `1`, and each `1` is repla
 ```JavaScript
 Input: image = [[1,1,0],[1,0,1],[0,0,0]]
 Output: [[1,0,0],[0,1,0],[1,1,1]]
-Explanation: First reverse each row: [[0,1,1],[1,0,1],[0,0,0]]
-             Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]
+Explanation: First reverse each row:
+             [[0,1,1],[1,0,1],[0,0,0]]
+             Then, invert the image:
+             [[1,0,0],[0,1,0],[1,1,1]]
 ```
 
 ### 2<sup>nd</sup> Example
 
 ```JavaScript
 Input: image = [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
 Output: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
-Explanation: First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]]
-             Then, invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
+Explanation: First reverse each row:
+             [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]]
+             Then, invert the image:
+             [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
 ```
 
 <br/>
@@ -49,9 +53,9 @@ Explanation: First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]]
 
 ```JavaScript
 const flipAndInvertImage = (image) => {
-    for(let row in image) {
+    for (let row in image) {
         image[row] = image[row].reverse();
-        image[row] = image[row].map(x=>1-x);
+        image[row] = image[row].map(x => 1 - x);
     }
 
     return image;

JavaScriptNumberOfIslands.md

@@ -62,7 +62,10 @@ const numIslands = (grid) => {
 };
 
 const dfs = (grid, row, col) => {
-    if (row < 0 || row >= grid.length || col < 0 || col >= grid[0].length) {
+    if (row < 0 ||
+        row >= grid.length ||
+        col < 0 ||
+        col >= grid[0].length) {
         return;
     }
 

JavaScriptTransposeMatrix.md

@@ -40,10 +40,10 @@ Output: [[1,4],[2,5],[3,6]]
 const transpose = (A) => {
     let result = [];
 
-    for (let i= 0; i<A[0].length; i++) {
+    for (let i = 0; i < A[0].length; i++) {
         let currentColumn = [];
 
-        for (let j=0; j<A.length; j++) {
+        for (let j = 0; j < A.length; j++) {
             currentColumn.push(A[j][i]);
         }
 

JavaScriptTwoSum.md

@@ -49,7 +49,7 @@ Output: [0,1]
 const twoSum = (nums, target) => {
     let numsObject = {};
 
-    for(let i = 0; i < nums.length; i++) {
+    for (let i = 0; i < nums.length; i++) {
         let n          = nums[i],
             compliment = target-n;
 
@@ -60,7 +60,7 @@ const twoSum = (nums, target) => {
         numsObject[n] = i;
     }
 
-    return [-1,-1];
+    return [-1, -1];
 };
 ```
 
@@ -80,7 +80,7 @@ A `for` loop is used to iterate through each element in the `nums` array. Within
 An `if` statement checks if the `numsObject` object has a property with the value of `compliment`. If such a property exists, it means that a pair of numbers that add up to the target has been found.
 <br/>
 
-In this case, the function returns an array containing the current index ( `i` ) and the index of the compliment in the `numsObject` object.
+In this case, the function returns an array containing the current index (`i`) and the index of the compliment in the `numsObject` object.
 <br/>
 
 If the compliment property does not exist, it means that the current number has not been encountered before. In that case, the current number (`n`) is added as a property to the `numsObject` object, with the value of the current index (`i`).