fix: return tableName in property.reference() (#51)(@leibowitz)

* fix: return tableName in property.reference()

Fix issue when foreign key is not defining a reference,
but a relationship exists, resulting in this:

Error: There are no resources with given id: "[object Object]"

Or

Error: There are no resources with given id: ""schema"."table""

* chore: temporarily cast references.model as any

Co-authored-by: Rafał Dzięgielewski <rafal.dzieg@gmail.com>

Author: leibowitz

src/property.ts

@@ -73,6 +73,9 @@ class Property extends BaseProperty {
     if (this.sequelizePath.references === 'string') {
       return this.sequelizePath.references as string;
     } if (this.sequelizePath.references && typeof this.sequelizePath.references !== 'string') {
+      if (this.sequelizePath.references.model && typeof this.sequelizePath.references.model !== 'string') {
+        return (this.sequelizePath.references?.model as any)?.tableName as string
+      }
       return this.sequelizePath.references?.model as string;
     }
     return null;