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Duo/tpv6 7 #48
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Original file line number | Diff line number | Diff line change |
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@@ -17,8 +17,8 @@ FL = 6 ! Friction law | |
!0: none, 16:LSW, 103: RS with strong velocity weakening | ||
!yaml file defining spatial dependance of fault properties | ||
ModelFileName = 'fault.yaml' | ||
v_star = 1 ! Prakash-Clifton regularization parameter | ||
L = 0.01 | ||
v_star = 0.1 ! Prakash-Clifton regularization parameter | ||
L = 0.5 | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. These values are not prescribed by the Benchmark, right? |
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!reference vector for defining strike and dip direction | ||
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@@ -29,7 +29,7 @@ refPointMethod = 1 | |
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RF_output_on = 1 ! Rupture front ascii output | ||
OutputPointType = 5 ! Type (0: no output, 3: ascii file, 4: paraview file, 5: 3+4) | ||
SlipRateOutputType=1 ! 0: (smoother) slip rate output evaluated from the difference between the velocity on both side of the fault | ||
SlipRateOutputType=0 ! 0: (smoother) slip rate output evaluated from the difference between the velocity on both side of the fault | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. I would not change that. |
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! 1: slip rate output evaluated from the fault tractions and the failure criterion (less smooth but usually more accurate where the rupture front is well developped) | ||
/ | ||
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@@ -58,7 +58,7 @@ PPFileName = 'tpv6_faultreceivers.dat' | |
/ | ||
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&MeshNml | ||
MeshFile = 'tpv5_f200m.puml.h5' | ||
MeshFile = 'tpv5_f200_halfdom_sym' | ||
meshgenerator = 'PUML' ! Name of meshgenerator (Gambit3D-fast, Netcdf or PUML) | ||
/ | ||
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@@ -75,8 +75,6 @@ OutputFile = 'output/tpv6' | |
Format = 10 ! Format (10= no output, 6=hdf5 output) | ||
! |stress |vel | ||
iOutputMask = 0 0 0 0 0 0 1 1 1 | ||
! |strain |eta | ||
iPlasticityMask = 0 0 0 0 0 0 1 | ||
TimeInterval = 5. ! Index of printed info at time | ||
refinement = 1 | ||
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should be 10000.