URI 2176 (Parity) Solution in C (string)

#include<stdio.h>
int main()
{
    char N[101]; //N is a string
    int i,count1=0;
    scanf("%s",&N);
 
    for(i=0; N[i]!='\0'; i++)
    {
        if(N[i]=='1') count1++;
    }
 
    if(count1%2==0) N[i]='0';     //if value of count1 is even/odd then
    else N[i]='1';                //0/1 will be added at the last of the
    N[i+1]='\0';                  //string N. So '\0' valu wil be replaced
    printf("%s\n",N);             //by 0/1.  so we need to add '\0' after
                                  //the replaced value in line 15.
    return 0;
}