URI 1332 - One-Two-Three solution in C (string)

#include <stdio.h>
#include <string.h>
int main()
{
    int t,len;
    char str[10];
    scanf("%d",&t);
    while(t>0)
    {
        t--;
        scanf("%s",&str);
        len=strlen(str);
        if(len == 5) printf("3\n");
        else if(len == 3)
        {
            if(str[0]=='o' && str[1]=='n' || str[0]=='o' && str[2]=='e' || str[1]=='n' && str[2]=='e')
                printf("1\n");
            else
                printf("2\n");
        }
    }

    return 0;
}