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| 1 | + /* Largest Number At Least Twice of Others |
| 2 | + You are given an integer array nums where the largest integer is unique. |
| 3 | +Determine whether the largest element in the array is at least twice as much as every other number in the array. |
| 4 | +If it is, print the index of the largest element, or print -1 otherwise. */ |
| 5 | + |
| 6 | +import java.util.*; |
| 7 | +public class Main |
| 8 | +{ |
| 9 | + public static void main(String[] args) { |
| 10 | + Scanner sc = new Scanner(System.in); |
| 11 | + int n =sc.nextInt(); |
| 12 | + int a[] = new int[n]; |
| 13 | + int max = Integer.MIN_VALUE; |
| 14 | + int maxindex =0; |
| 15 | + for(int i=0;i<n;i++){ |
| 16 | + a[i]=sc.nextInt(); |
| 17 | + if(a[i]>max){ |
| 18 | + max =a[i]; |
| 19 | + maxindex =i; |
| 20 | + } |
| 21 | + |
| 22 | + } |
| 23 | + boolean flag = false; |
| 24 | + for(int i=0;i<n;i++){ |
| 25 | + if( i!=maxindex && max < 2*a[i]){ |
| 26 | + flag = true; |
| 27 | + } |
| 28 | + } |
| 29 | + if(flag){ |
| 30 | + System.out.println(-1); |
| 31 | + } |
| 32 | + else{ |
| 33 | + System.out.println(maxindex); |
| 34 | + } |
| 35 | + |
| 36 | + } |
| 37 | +} |
| 38 | + |
| 39 | + |
| 40 | +/* PEAK ELEMENT |
| 41 | +An element is called a peak element if its value is not smaller than the value of its adjacent elements(if they exists). Given an array arr[] of size n, find the index of first peak element. If peak element does not exist print -1. |
| 42 | + |
| 43 | +Input |
| 44 | +line 1: contains an integer n denoting size of array. |
| 45 | + |
| 46 | +line 2: contains n spaced integers denoting elements of array. |
| 47 | + |
| 48 | +Output |
| 49 | +Print a single integer denoting the index of first peak element in array. If no such element exists, print -1. */ |
| 50 | +import java.util.*; |
| 51 | +public class Main |
| 52 | +{ |
| 53 | + public static void main(String[] args) { |
| 54 | + Scanner sc = new Scanner(System.in); |
| 55 | + int n =sc.nextInt(); |
| 56 | + int a[] = new int[n]; |
| 57 | + for(int i=0;i<n;i++){ |
| 58 | + a[i]=sc.nextInt(); |
| 59 | + |
| 60 | + } |
| 61 | + if(n==1){ |
| 62 | + System.out.println(0); |
| 63 | + return; |
| 64 | + } |
| 65 | + if(a[0]>a[1] ){ |
| 66 | + System.out.println(0); |
| 67 | + return; |
| 68 | + } |
| 69 | + |
| 70 | + for(int i=1;i<n-1;i++){ |
| 71 | + if(a[i]>a[i+1] &&a[i]>a[i-1]){ |
| 72 | + System.out.println(i); |
| 73 | + return; |
| 74 | + } |
| 75 | + } |
| 76 | + |
| 77 | + if(a[n-1]>a[n-2]){ |
| 78 | + System.out.println(n-1); |
| 79 | + return; |
| 80 | + } |
| 81 | + |
| 82 | + System.out.println(-1); |
| 83 | + |
| 84 | + } |
| 85 | +} |
| 86 | + /* SUM OF ARRAY EXCEPT SELF */ |
| 87 | + import java.util.*; |
| 88 | +public class Main |
| 89 | +{ |
| 90 | + public static void main(String[] args) { |
| 91 | + Scanner sc = new Scanner(System.in); |
| 92 | + int n =sc.nextInt(); |
| 93 | + int a[] = new int[n]; |
| 94 | + int sum =0; |
| 95 | + for(int i=0;i<n;i++){ |
| 96 | + a[i]=sc.nextInt(); |
| 97 | + sum += a[i]; |
| 98 | + |
| 99 | + } |
| 100 | + for(int i=0;i<n;i++){ |
| 101 | + System.out.print(sum-a[i] +" "); |
| 102 | + } |
| 103 | + |
| 104 | + |
| 105 | + } |
| 106 | +} |
| 107 | + // largest and second largest number in an array |
| 108 | + |
| 109 | + import java.util.*; |
| 110 | +public class Main |
| 111 | +{ |
| 112 | + public static void main(String[] args) { |
| 113 | + Scanner sc = new Scanner(System.in); |
| 114 | + int n =sc.nextInt(); |
| 115 | + int a[] = new int[n]; |
| 116 | + int max =Integer.MIN_VALUE; |
| 117 | + int secondmax = Integer.MIN_VALUE; |
| 118 | + for(int i=0;i<n;i++){ |
| 119 | + a[i]=sc.nextInt(); |
| 120 | + if(a[i]>max){ |
| 121 | + secondmax = max; |
| 122 | + max = a[i]; |
| 123 | + } |
| 124 | + else if(a[i]>secondmax){ |
| 125 | + secondmax =a[i]; |
| 126 | + } |
| 127 | + } |
| 128 | + |
| 129 | + System.out.println(max); |
| 130 | + System.out.println(secondmax); |
| 131 | + |
| 132 | + } |
| 133 | +} |
| 134 | + |
| 135 | + |
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