925

Author: ProHiryu

code/925.long-pressed-name.py

@@ -0,0 +1,24 @@
+#
+# @lc app=leetcode id=925 lang=python3
+#
+# [925] Long Pressed Name
+#
+
+# @lc code=start
+class Solution:
+    def isLongPressedName(self, name: str, typed: str) -> bool:
+        m = len(name)
+        n = len(typed)
+        
+        i, j = 0, 0
+        while j < n:
+            if (i < m) and (name[i] == typed[j]):
+                i += 1
+                j += 1
+            else:
+                if (j > 0) and (typed[j] == typed[j - 1]):
+                    j += 1
+                else:
+                    return False
+        return i == m
+