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This PR adds the Rotate Array algorithm implemented in Python.
The problem rotates the elements of an array to the right by k steps, modifying the array in-place.

Key Details:

Algorithm Used: Array rotation using the Three-Reverse Technique

Time Complexity: O(n)

Space Complexity: O(1) (in-place rotation)

Alternate Approach: Also includes a secondary version using an extra array (O(n) space) for reference.

Approach:

Reverse the entire array.

Reverse the first k elements.

Reverse the remaining n–k elements.
This approach avoids additional space while maintaining linear time performance.

Files Added:

rotate_array.py → Core implementation with docstrings, helper functions, and examples.

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💎 Code Quality Check Results

❌ Missing Algorithm Description

These files don't explain what the algorithm does:

  • Python/algorithms/mathematical/rotate_array.py

Required: Add a description explaining the algorithm, its purpose, and how it works

📚 Quality Standards

To maintain high quality, every contribution should include:

  1. ✍️ Algorithm Description

    • Explain what the algorithm does
    • Describe the approach and methodology
    • Include use cases or applications
  2. 📊 Complexity Analysis

    • Time complexity (e.g., O(n log n))
    • Space complexity (e.g., O(n))
    • Brief explanation of why
  3. 💬 Meaningful Comments

    • Explain complex logic
    • Document function parameters
    • Add inline comments for clarity
  4. ✅ Test Cases/Examples

    • Demonstrate the code works
    • Show different input scenarios
    • Include edge cases

💡 Example Template

"""
Binary Search Algorithm

Description: Searches for a target value in a sorted array using divide-and-conquer

Time Complexity: O(log n) - halves search space each iteration
Space Complexity: O(1) - only uses constant extra space
"""

def binary_search(arr, target):
    # Initialize pointers
    left, right = 0, len(arr) - 1

    while left <= right:
        mid = (left + right) // 2

        # Check if target found
        if arr[mid] == target:
            return mid
        # Search right half
        elif arr[mid] < target:
            left = mid + 1
        # Search left half
        else:
            right = mid - 1

    return -1  # Not found

# Test cases
if __name__ == "__main__":
    test_arr = [1, 3, 5, 7, 9]
    print(binary_search(test_arr, 5))  # Output: 2
    print(binary_search(test_arr, 6))  # Output: -1

🔧 How to Fix

  1. Review each file mentioned above
  2. Add the missing documentation
  3. Push your changes
  4. The workflow will re-run automatically

💪 You've Got This!

These checks help maintain quality and make your contribution more valuable to learners. Thank you for taking the time to improve! 🙏


Quality over quantity - let's build something amazing together! 🌟

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🎉 Welcome to Hacktoberfest 2025, @MeloveGupta! 🎃

Thank you for your first contribution to our DSA repository! Here's what happens next:

🔍 Automatic Checks

  • Code Validation: Passed
  • 🧪 Compilation Tests: Passed

📋 Next Steps

🎯 Great job! Your code compiled successfully. Maintainers @Karanjot786 and @Pradeepsingh61 will review your PR soon.

🎁 What You Get

  • 🏆 Hacktoberfest Credit: This PR counts toward your 6 PR goal for exclusive T-shirt + Tree!
  • 🌟 Hall of Fame: You'll be featured in our contributors list
  • 📚 Learning: Code review feedback from experienced developers

💡 Tips for Success

  • Follow our Contributing Guidelines
  • Add comments explaining your algorithm
  • Include time/space complexity analysis
  • Test your code before submitting

Welcome to the community! 🚀

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🤖 Automated PR Status

🔍 Code Validation

Passed - File naming and structure look good!

🧪 Compilation Tests

Passed - All code compiles successfully!

📋 Overall Status

🎉 Ready for Review - Your PR has passed all automated checks!
👥 Maintainers have been notified for review.


This comment was generated automatically. Checks will re-run when you push new commits.

@github-actions github-actions bot requested a review from Karanjot786 October 27, 2025 06:33
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