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Author: MathProgrammer

Explanations/Explanations - 10/Keyboard Layouts Explanation.txt

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+There are two popular keyboard layouts in Berland, they differ only in letters positions. All the other keys are the same. 
+In Berland they use alphabet with 26 letters which coincides with English alphabet.
+
+You are given two strings consisting of 26 distinct letters each: all keys of the first and the second layouts in the same order.
+
+You are also given some text consisting of small and capital English letters and digits. It is known that it was typed in the first layout, 
+but the writer intended to type it in the second layout. Print the text if the same keys were pressed in the second layout.
+
+Since all keys but letters are the same in both layouts, the capitalization of the letters should remain the same, as well as all other characters.
+
+Input
+The first line contains a string of length 26 consisting of distinct lowercase English letters. This is the first layout.
+
+The second line contains a string of length 26 consisting of distinct lowercase English letters. This is the second layout.
+
+The third line contains a non-empty string s consisting of lowercase and uppercase English letters and digits. This is the text typed in the first layout. 
+The length of s does not exceed 1000.
+
+Output
+Print the text if the same keys were pressed in the second layout.
+
+-----------------------------------------------------------
+
+I did this by making a <char, int> map ... the first keyboard's characters are mapped to a position number.
+Then, when the input is read ... I display second_keyboard[map[i]] ...But, it can be done easier and better with a <char, char> map.
+
+That way ... program is easier and cleaner.
+
+If the character is not an alphabet, just display it as it is. Otherwise, check if it is capital or not and print the corresponding character after checking case.
+
+--------------------------------------------------
+
+int main()
+{
+    char keyboard_1[NO_OF_ALPHABETS], keyboard_2[NO_OF_ALPHABETS];
+    scanf("%s %s", keyboard_1, keyboard_2);
+
+    map <char, char> corresponding_keyboard_2_char;
+    for(int i = 0; i < NO_OF_ALPHABETS; i++)
+    {
+        corresponding_keyboard_2_char[ keyboard_1[i] ] = keyboard_2[i];
+    }
+
+    char text[MAX_LENGTH];
+    scanf("%s", text);
+
+    for(int i = 0; text[i] != '\0'; i++)
+    {
+        if(isalpha(text[i]))
+        {
+            char input = tolower(text[i]);
+            putchar(is_capital(text[i]) ? tocapital(corresponding_keyboard_2_char[input]) : corresponding_keyboard_2_char[input]);
+        }
+        else
+        {
+            putchar(text[i]); //Not there in the keyboards
+        }
+    }
+    return 0;
+}