My answer to the second programming assignment version rdpeng#1

Author: Markmydata

cachematrix.R

@@ -1,15 +1,33 @@
-## Put comments here that give an overall description of what your
-## functions do
+## These functions combined, will be able to return an inverse of a matrix. 
+## The function is written so that, should a matrix have remained the same, it will returned it's previously cached result, rather than computing the inverse again,
+## making the solution more efficient. 
 
-## Write a short comment describing this function
+## makeCachematrix creates a 'special' matrix out of a simple matrix and makes it able to store the inverse in the cached memory
 
 makeCacheMatrix <- function(x = matrix()) {
-
+m <- NULL
+set <- function(y){
+        x <<- y
+        m <<- NULL
+}
+get <- function() x
+setsolve <- function(solve) m <<- solve
+getsolve <- function() m
+list(set = set, get = get, setsolve = setsolve, getsolve = getsolve)
 }
 
 
-## Write a short comment describing this function
+## cacheSolve checks to see if the special matrix matches the special matrix from the previously cached inverse, and returns the cached inverse if true. 
+## Should the special matrix have been altered, it computes and returns the appropriate inverse. 
 
 cacheSolve <- function(x, ...) {
-        ## Return a matrix that is the inverse of 'x'
+        m <- x$getsolve()
+        if(!is.null(m)){
+                message("getting cached data")
+                return(m)
+        }
+        data <- x$get()
+        m <- solve(data,...)
+        x$setsolve(m)
+        m
 }