Doc Example

[iwelch]

I am trying to get the doc example to work:

f(x,y) = log(x+y)
xs = 1:0.2:5
ys = 2:0.1:5
A = [f(x+y) for x in xs, y in ys]

# linear interpolation
interp_linear = LinearInterpolation((xs, ys), A)

I think the first error is that you mean f(x,y) instead of f(x+y).

but even then,

julia> A = [f(x,y) for x in xs, y in ys]
5×4 Array{Float64,2}:
 1.09861  1.38629  1.60944  1.79176
 1.38629  1.60944  1.79176  1.94591
 1.60944  1.79176  1.94591  2.07944
 1.79176  1.94591  2.07944  2.19722
 1.94591  2.07944  2.19722  2.30259

julia> interp_linear = LinearInterpolation((xs, ys), A)
ERROR: MethodError: no method matching LinearInterpolation(::Tuple{UnitRange{Int64},StepRange{Int64,Int64}}, ::Array{Float64,2})
Closest candidates are:
  LinearInterpolation(::T<:AbstractRange, ::Any; extrapolation_bc) where T<:AbstractRange at /Users/ivo/.julia/packages/Interpolations/qyX2d/src/convenience-constructors.jl:3
  LinearInterpolation(::T<:AbstractArray, ::Any; extrapolation_bc) where T<:AbstractArray at /Users/ivo/.julia/packages/Interpolations/qyX2d/src/convenience-constructors.jl:4
  LinearInterpolation(::Tuple{Vararg{T<:AbstractRange,N}}, ::Any; extrapolation_bc) where {N, T<:AbstractRange} at /Users/ivo/.julia/packages/Interpolations/qyX2d/src/convenience-constructors.jl:8
  ...
Stacktrace:
 [1] top-level scope at none:0

ultimately, I want to find out whether I can manipulate an irregular (x,y,z) data set into a contour plot (which can accept irregular x and y, but needs a function for z, rather than a value).

[timholy]

Modulo the comma in f, your example works for me. But I don't think you actually showed what you're trying: note the UnitRange in the signature of the MethodError.

[timholy]

I made a guess about what you were actually trying to do and committed a fix in #241. Feel free to reopen if this doesn't fix your underlying problem.