Support converting Fills to StepRangeLen (#290)

Author: dlfivefifty

Project.toml

@@ -1,6 +1,6 @@
 name = "FillArrays"
 uuid = "1a297f60-69ca-5386-bcde-b61e274b549b"
-version = "1.5.0"
+version = "1.6.0"
 
 [deps]
 LinearAlgebra = "37e2e46d-f89d-539d-b4ee-838fcccc9c8e"

src/FillArrays.jl

@@ -530,6 +530,9 @@ function convert(::Type{T}, A::AbstractFillMatrix) where T<:Diagonal
     isdiag(A) ? T(A) : throw(InexactError(:convert, T, A))
 end
 
+Base.StepRangeLen(F::AbstractFillVector{T}) where T = StepRangeLen(getindex_value(F), zero(T), length(F))
+convert(::Type{SL}, F::AbstractFillVector) where SL<:AbstractRange = convert(SL, StepRangeLen(F))
+
 #################
 # Structured matrix types
 #################

test/runtests.jl

@@ -301,6 +301,13 @@ end
         @test A[1,:,1] ≡ A[1,1:6,1] ≡ Fill(2.0,6)
         @test A[:,:,:] ≡ A[1:5,1:6,1:7] ≡ A[1:5,:,1:7] ≡ A[:,1:6,1:7] ≡ A
     end
+
+    @testset "StepRangeLen convert" begin
+        for (z,s) in  ((Zeros{Int}(5), StepRangeLen(0, 0, 5)), (Ones{Int}(5), StepRangeLen(1, 0, 5)), (Fill(2,5), StepRangeLen(2, 0, 5)))
+            @test s == z
+            @test StepRangeLen(z) ≡ convert(StepRangeLen, z) ≡ convert(StepRangeLen{Int}, z) ≡ convert(typeof(s), z) ≡ convert(AbstractRange, z) ≡ s
+        end
+    end
 end
 
 @testset "RectDiagonal" begin