diff --git a/1207-Unique-Number-of-Occurences.py b/1207-Unique-Number-of-Occurences.py new file mode 100644 index 0000000..035ca31 --- /dev/null +++ b/1207-Unique-Number-of-Occurences.py @@ -0,0 +1,40 @@ +''' +Given an array of integers arr, write a function that returns true if and only if the number of occurrences of each value in the array is unique. + + + +Example 1: + +Input: arr = [1,2,2,1,1,3] +Output: true +Explanation: The value 1 has 3 occurrences, 2 has 2 and 3 has 1. No two values have the same number of occurrences. + +Example 2: + +Input: arr = [1,2] +Output: false + +Example 3: + +Input: arr = [-3,0,1,-3,1,1,1,-3,10,0] +Output: true + + + +Constraints: + + 1 <= arr.length <= 1000 + -1000 <= arr[i] <= 1000 + +''' +class Solution: + def uniqueOccurrences(self, arr: List[int]) -> bool: + d = {} + for i in range(len(arr)): + d[arr[i]] = d.get(arr[i],0) + 1 + s = set() + for i,j in d.items(): + if j in s: + return False + s.add(j) + return True