colors.py

# A couple different color based ones
import random

color_choice = random.choice(
	["FF0000", "00FF00", "0000FF", "FFFF00", "00FFFF", "FF00FF"]
)  # Red Green Blue Yellow Cyan Magenta


# Must contain only two primary colors
def primary(i, password):
	# Check if password has primary color
	x = 0
	for color in ["blue", "red", "green"]:
		if color in password.lower():
			x += 1
	# Pass check
	if x == 2:
		return True
	# Did not pass
	if x == 1:
		print(
			"Rule "
			+ str(i)
			+ ": Password must include one more primary color (Science/Computing based primary colors)."
		)
	elif x > 2:
		print(
			"Rule "
			+ str(i)
			+ ": Password must include only two primary colors (Science/Computing based primary colors)."
		)
	else:
		print(
			"Rule "
			+ str(i)
			+ ": Password must include two primary colors (Science/Computing based primary colors)."
		)
	return False


# Must contain the mix of the two primary colors
def secondary(i, password):
	# Get the first 2 primary colours
	colors = []
	for color in ["blue", "red", "green"]:
		if color in password.lower():
			if color not in colors and len(colors) < 2:
				colors.append(color)
	# Decide what the mixture is
	x = []
	if "blue" in colors and "red" in colors:
		x = ["magenta", "purple", "pink", "lilac", "violet"]
	elif "red" in colors and "green" in colors:
		x = ["yellow"]
	elif "green" in colors and "blue" in colors:
		x = ["cyan", "turquoise"]
	# Test if mixture is in password
	for y in x:
		if y in password.lower():
			return True
	# Did not pass
	print(
		"Rule "
		+ str(i)
		+ ": Password must include the mixture of your two primary colors."
	)
	return False


# Must only contain a single secondary color
def multiplesecondary(i, password):
	# Count up each color
	t = 0
	for c in [
		"magenta",
		"purple",
		"pink",
		"lilac",
		"violet",
		"yellow",
		"cyan",
		"turquoise",
	]:
		if c in password.lower():
			t += 1
	# Test if there is less than or equal to 1 in total
	if t <= 1:
		return True
	# Did not pass
	print("Rule " + str(i) + ": Password must only contain a single secondary color.")
	return False


# Must contain this color in text
def hextotext(i, password):
	# Setup choices
	choices = []
	if color_choice == "FF0000":
		choices = ["red"]
	elif color_choice == "00FF00":
		choices = ["green"]
	elif color_choice == "0000FF":
		choices = ["blue"]
	elif color_choice == "FFFF00":
		choices = ["yellow"]
	elif color_choice == "00FFFF":
		choices = ["cyan", "turquoise"]
	elif color_choice == "FF00FF":
		choices = ["magenta", "purple", "pink", "lilac", "violet"]
	# For each choice test if it is in password
	for color in choices:
		if color in password.lower():
			return True
	# Did not pass
	print(
		"Rule "
		+ str(i)
		+ ": Password must include the name of the color #"
		+ color_choice
		+ " (That is hexadecimal rgb)."
	)
	return False