|
| 1 | +/** |
| 2 | + * Definition for a binary tree node. |
| 3 | + * public class TreeNode { |
| 4 | + * public var val: Int |
| 5 | + * public var left: TreeNode? |
| 6 | + * public var right: TreeNode? |
| 7 | + * public init() { self.val = 0; self.left = nil; self.right = nil; } |
| 8 | + * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; } |
| 9 | + * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) { |
| 10 | + * self.val = val |
| 11 | + * self.left = left |
| 12 | + * self.right = right |
| 13 | + * } |
| 14 | + * } |
| 15 | + */ |
| 16 | +class Solution { |
| 17 | + // O(n * m) time / O(n) space |
| 18 | + func isSubtree(_ root: TreeNode?, _ subRoot: TreeNode?) -> Bool { |
| 19 | + let subRootNode = subRoot?.val |
| 20 | + |
| 21 | + var queue = [TreeNode]() |
| 22 | + guard let root = root else { |
| 23 | + return false |
| 24 | + } |
| 25 | + queue.append(root) |
| 26 | + var head = 0 |
| 27 | + while queue.count > head { |
| 28 | + let currentNode = queue[head] |
| 29 | + head += 1 |
| 30 | + if currentNode.val == subRootNode { |
| 31 | + if dfs(node: currentNode, subRoot: subRoot) { |
| 32 | + return true |
| 33 | + } |
| 34 | + } |
| 35 | + |
| 36 | + if let left = currentNode.left { |
| 37 | + queue.append(left) |
| 38 | + } |
| 39 | + if let right = currentNode.right { |
| 40 | + queue.append(right) |
| 41 | + } |
| 42 | + } |
| 43 | + |
| 44 | + return false |
| 45 | + } |
| 46 | + |
| 47 | + func dfs(node: TreeNode?, subRoot: TreeNode?) -> Bool { |
| 48 | + guard let node = node, let subRoot = subRoot else { |
| 49 | + return node == nil && subRoot == nil |
| 50 | + } |
| 51 | + |
| 52 | + return node.val == subRoot.val |
| 53 | + && dfs(node: node.left, subRoot: subRoot.left) |
| 54 | + && dfs(node: node.right, subRoot: subRoot.right) |
| 55 | + } |
| 56 | + |
| 57 | +} |
0 commit comments