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Add day 14
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‎day14/Java/Product.java‎

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import java.util.Scanner;
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public class Product {
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public static int recursiveProd (int num1, int num2) {
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if (num2 == 1)
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return num1;
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// If any of the numbers is zero, return 0
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if (num1 == 0 || num2 == 0)
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return 0;
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// If both numbers are less than zero negative signs can be removed
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if (num1 < 0 && num2 < 0)
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return recursiveProd (-1*num1, -1*num2);
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else if (num2 < 0)
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return recursiveProd (num2, num1);
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else
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return num1 + recursiveProd(num1, num2-1);
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}
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public static void main(String[] args) {
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Scanner input = new Scanner (System.in);
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System.out.println("/* ===== Product of numbers using recursion ===== */");
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// Take input
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System.out.print("\nEnter first number: ");
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int num1 = input.nextInt();
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System.out.print("Enter second number: ");
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int num2 = input.nextInt();
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// Print the result
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System.out.println("Product of numbers " + num1 + " and " + num2 + " is: " + recursiveProd(num1, num2));
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}
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}

‎day14/Java/SumDigits.java‎

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/**
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* @author MadhavBahlMD
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* @date 08/01//2018
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*/
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import java.util.Scanner;
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public class SumDigits {
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public static int sum (int num) {
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if (num/10 < 1)
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return num;
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else
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return (num%10) + sum(num/10);
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}
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public static void main(String[] args) {
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Scanner input = new Scanner (System.in);
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System.out.println("/* ===== Sum of digits using recursion ===== */");
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System.out.print("\nEnter a number: ");
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int num = input.nextInt();
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System.out.println("Sum of digits of " + num + " is: " + sum(num));
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}
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}

‎day14/JavaScript/prod_madhav.js‎

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/**
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* @author MadhavBahlMD
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* @date 08/01/2018
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* METHOD - We keep thte second argument (num2) positive and add the first arguement num2(second arg) times
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*/
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function recursiveProd (num1, num2) {
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// If num 2 becomes 1, return num1
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if (num2 === 1)
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return num1;
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// If any of the numbers is zero, return 0
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if (num1 === 0 || num2 === 0)
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return 0;
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// If both numbers are less than zero negative signs can be removed
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if (num1 < 0 && num2 < 0)
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return recursiveProd (-1*num1, -1*num2);
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else if (num2 < 0)
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return recursiveProd (num2, num1);
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else
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return num1 + recursiveProd(num1, num2-1);
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}
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let n1 = 5, n2 = 10;
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console.log (`${n1} x ${n2} = ${recursiveProd(n1, n2)}`);
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let n3 = -8, n4 = 4;
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console.log (`${n3} x ${n4} = ${recursiveProd(n3, n4)}`);
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let n5 = 2, n6 = -7;
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console.log (`${n5} x ${n6} = ${recursiveProd(n5, n6)}`);
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let n7 = -4, n8 = -7;
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console.log (`${n7} x ${n8} = ${recursiveProd(n7, n8)}`);

‎day14/JavaScript/sum_madhav.js‎

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/**
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* @author MadhavBahlMD
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* @date 08/01/2018
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*/
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function sumDigits (num) {
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if (num/10 < 1)
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return num;
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else
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return (num % 10) + sumDigits (parseInt(num/10));
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}
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let num1 = 12345, num2 = 91827;
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console.log(`Sum of digits of ${num1} is ${sumDigits(num1)}`);
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console.log(`Sum of digits of ${num2} is ${sumDigits(num2)}`);

‎day14/README.md‎

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![cover](./cover.png)
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# Day 14 - Recursion Series Part B
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Today's Problems - Sum of digits and product of numbers
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## Question 1
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Given a number, write a program to find the sum of it's digits using recursion
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**Example**
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```
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input: 12345
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output: 15
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input: 91827
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output: 27
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```
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## Question 2
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Given 2 numbers, write a program to find their product using recursion
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**Example**
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```
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input: 10,5
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output: 50
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input: -8,4
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output: -32
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```
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**Hint**: Multiplication is repeated addition!
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![ques](./ques.png)
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## Part A - Sum of Digits
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### JavaScript Implementation
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#### [Solution](./JavaScript/sum_madhav.js)
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```js
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/**
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* @author MadhavBahlMD
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* @date 08/01/2018
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*/
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function sumDigits (num) {
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if (num/10 < 1)
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return num;
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else
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return (num % 10) + sumDigits (parseInt(num/10));
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}
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let num1 = 12345, num2 = 91827;
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console.log(`Sum of digits of ${num1} is ${sumDigits(num1)}`);
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console.log(`Sum of digits of ${num2} is ${sumDigits(num2)}`);
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```
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### Java Implementation
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#### [Solution](./Java/SumDigits.java)
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```java
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/**
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* @author MadhavBahlMD
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* @date 08/01//2018
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*/
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import java.util.Scanner;
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public class SumDigits {
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public static int sum (int num) {
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if (num/10 < 1)
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return num;
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else
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return (num%10) + sum(num/10);
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}
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public static void main(String[] args) {
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Scanner input = new Scanner (System.in);
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System.out.println("/* ===== Sum of digits using recursion ===== */");
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System.out.print("\nEnter a number: ");
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int num = input.nextInt();
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System.out.println("Sum of digits of " + num + " is: " + sum(num));
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}
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}
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```
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<hr />
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## Part B - Product of numbers
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### JavaScript Implementation
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#### [Solution](./JavaScript/prod_madhav.js)
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```js
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/**
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* @author MadhavBahlMD
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* @date 08/01/2018
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* METHOD - We keep thte second argument (num2) positive and add the first arguement num2(second arg) times
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*/
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function recursiveProd (num1, num2) {
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// If num 2 becomes 1, return num1
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if (num2 === 1)
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return num1;
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// If any of the numbers is zero, return 0
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if (num1 === 0 || num2 === 0)
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return 0;
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// If both numbers are less than zero negative signs can be removed
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if (num1 < 0 && num2 < 0)
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return recursiveProd (-1*num1, -1*num2);
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else if (num2 < 0)
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return recursiveProd (num2, num1);
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else
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return num1 + recursiveProd(num1, num2-1);
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}
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let n1 = 5, n2 = 10;
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console.log (`${n1} x ${n2} = ${recursiveProd(n1, n2)}`);
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let n3 = -8, n4 = 4;
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console.log (`${n3} x ${n4} = ${recursiveProd(n3, n4)}`);
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let n5 = 2, n6 = -7;
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console.log (`${n5} x ${n6} = ${recursiveProd(n5, n6)}`);
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let n7 = -4, n8 = -7;
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console.log (`${n7} x ${n8} = ${recursiveProd(n7, n8)}`);
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```
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### Java Implementation
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#### [Solution](./Java/Product.java)
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```java
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/**
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* @author MadhavBahlMD
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* @date 08/01//2018
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*/
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import java.util.Scanner;
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public class Product {
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public static int recursiveProd (int num1, int num2) {
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if (num2 == 1)
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return num1;
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// If any of the numbers is zero, return 0
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if (num1 == 0 || num2 == 0)
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return 0;
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// If both numbers are less than zero negative signs can be removed
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if (num1 < 0 && num2 < 0)
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return recursiveProd (-1*num1, -1*num2);
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else if (num2 < 0)
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return recursiveProd (num2, num1);
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else
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return num1 + recursiveProd(num1, num2-1);
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}
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public static void main(String[] args) {
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Scanner input = new Scanner (System.in);
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System.out.println("/* ===== Product of numbers using recursion ===== */");
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// Take input
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System.out.print("\nEnter first number: ");
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int num1 = input.nextInt();
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System.out.print("Enter second number: ");
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int num2 = input.nextInt();
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// Print the result
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System.out.println("Product of numbers " + num1 + " and " + num2 + " is: " + recursiveProd(num1, num2));
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}
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}
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```

‎day14/cover.png‎

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‎day14/ques.png‎

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