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fix: 2.3 solutions
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2. SQL queries to related tables/2.2 Select join queries/solutions.sql

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@@ -53,3 +53,10 @@ ORDER BY b.title;
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/* Посчитать количество экземпляров книг каждого автора из таблицы author.
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Вывести тех авторов, количество книг которых меньше 10,
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в отсортированном по возрастанию количества виде. Последний столбец назвать Количество.*/
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SELECT a.name_author, SUM(b.amount) AS 'Количество'
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FROM book b
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RIGHT JOIN author a ON b.author_id = a.author_id
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GROUP BY a.name_author
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HAVING SUM(b.amount) < 10 OR SUM(b.amount) IS NULL
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ORDER BY 'Количество';
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