net/mlx4_en: Resolve dividing by zero in 32-bit system

When doing roundup_pow_of_two for large enough number with
bit 31, an overflow will occur and a value equal to 1 will
be returned. In this case 1 will be subtracted from the return
value and division by zero will be reached.

Fixes: 31c128b ("net/mlx4_en: Choose time-stamping shift value according to HW frequency")
Signed-off-by: Eugenia Emantayev <eugenia@mellanox.com>
Signed-off-by: Tariq Toukan <tariqt@mellanox.com>
Signed-off-by: David S. Miller <davem@davemloft.net>

Author: Eugenia Emantayev

drivers/net/ethernet/mellanox/mlx4/en_clock.c

@@ -245,8 +245,11 @@ static u32 freq_to_shift(u16 freq)
 {
 	u32 freq_khz = freq * 1000;
 	u64 max_val_cycles = freq_khz * 1000 * MLX4_EN_WRAP_AROUND_SEC;
+	u64 tmp_rounded =
+		roundup_pow_of_two(max_val_cycles) > max_val_cycles ?
+		roundup_pow_of_two(max_val_cycles) - 1 : UINT_MAX;
 	u64 max_val_cycles_rounded = is_power_of_2(max_val_cycles + 1) ?
-		max_val_cycles : roundup_pow_of_two(max_val_cycles) - 1;
+		max_val_cycles : tmp_rounded;
 	/* calculate max possible multiplier in order to fit in 64bit */
 	u64 max_mul = div_u64(0xffffffffffffffffULL, max_val_cycles_rounded);