You might know some pretty large perfect squares. But what about the NEXT one?
Complete the findNextSquare method that finds the next integral perfect square after the one passed as a parameter. Recall that an integral perfect square is an integer n such that sqrt(n) is also an integer.
If the parameter is itself not a perfect square, than -1 should be returned. You may assume the parameter is positive.
Examples:
findNextSquare(121) --> returns 144 findNextSquare(625) --> returns 676 findNextSquare(114) --> returns -1 since 114 is not a perfect
def find_next_square(sq)
number = Math.sqrt(sq) + 1
number % 1 == 0 ? number**2 : -1
end