Given a set of distinct integers, nums, return all possible subsets (the power set).
Note: The solution set must not contain duplicate subsets.
For example, If nums = [1,2,3], a solution is:
[
[3],
[1],
[2],
[1,2,3],
[1,3],
[2,3],
[1,2],
[]
]
求集合中所有子集问题
要求子集中元素非递减序排列,所以需要将原数组排序,所以构造子集方法可以构造一个二叉树或从第二层开始迭代
class Solution {
public:
vector<vector<int>> subsets(vector<int>& nums) {
vector<vector<int>> result(1);
sort(nums.begin(),nums.end());
int i=0,j=0;
for(i=0;i<nums.size();i++)
{
int resultsize=result.size();
for(j=0;j<resultsize;j++)
{
result.push_back(result[j]);
result.back().push_back(nums[i]);
}
}
return result;
}
};