Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.
Example:
Input: n = 4, k = 2 Output: [ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ] ##编程实现
vector<vector<int>> combine(int n, int k)
{
vector<vector<int>> result;
vector<int> solution;
dfs(result, solution, n, k, 1);
return result;
}
void dfs(vector<vector<int>>& result, vector<int>& solution, int n, int k, int start)
{
if (solution.size() == k)
{
result.push_back(solution);
return;
}
for (int i = start; i <= n; i++)
{
solution.push_back(i);
dfs(result, solution, n, k, i + 1);
solution.pop_back();
}
}